x(x+1)+(x+1)(x+2)=(x+2)(x+3)+x(x+4)-9

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Solution for x(x+1)+(x+1)(x+2)=(x+2)(x+3)+x(x+4)-9 equation:



x(x+1)+(x+1)(x+2)=(x+2)(x+3)+x(x+4)-9
We move all terms to the left:
x(x+1)+(x+1)(x+2)-((x+2)(x+3)+x(x+4)-9)=0
We multiply parentheses
x^2+x+(x+1)(x+2)-((x+2)(x+3)+x(x+4)-9)=0
We multiply parentheses ..
x^2+(+x^2+2x+x+2)+x-((x+2)(x+3)+x(x+4)-9)=0
We calculate terms in parentheses: -((x+2)(x+3)+x(x+4)-9), so:
(x+2)(x+3)+x(x+4)-9
We multiply parentheses
x^2+(x+2)(x+3)+4x-9
We multiply parentheses ..
x^2+(+x^2+3x+2x+6)+4x-9
We get rid of parentheses
x^2+x^2+3x+2x+4x+6-9
We add all the numbers together, and all the variables
2x^2+9x-3
Back to the equation:
-(2x^2+9x-3)
We get rid of parentheses
x^2+x^2-2x^2+2x+x+x-9x+2+3=0
We add all the numbers together, and all the variables
-5x+5=0
We move all terms containing x to the left, all other terms to the right
-5x=-5
x=-5/-5
x=1

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