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x(x+1)-195/4=0
We multiply parentheses
x^2+x-195/4=0
We multiply all the terms by the denominator
x^2*4+x*4-195=0
Wy multiply elements
4x^2+4x-195=0
a = 4; b = 4; c = -195;
Δ = b2-4ac
Δ = 42-4·4·(-195)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-56}{2*4}=\frac{-60}{8} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+56}{2*4}=\frac{52}{8} =6+1/2 $
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