x(x+1)=(x+2)(x-4)

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Solution for x(x+1)=(x+2)(x-4) equation: 



x(x+1)=(x+2)(x-4)

We move all terms to the left:

x(x+1)-((x+2)(x-4))=0

We multiply parentheses

x^2+x-((x+2)(x-4))=0

We multiply parentheses ..

x^2-((+x^2-4x+2x-8))+x=0



We calculate terms in parentheses: -((+x^2-4x+2x-8)), so:

(+x^2-4x+2x-8)

We get rid of parentheses

x^2-4x+2x-8

We add all the numbers together, and all the variables

x^2-2x-8

Back to the equation:

-(x^2-2x-8)



We add all the numbers together, and all the variables

x^2+x-(x^2-2x-8)=0

We get rid of parentheses

x^2-x^2+x+2x+8=0

We add all the numbers together, and all the variables

3x+8=0

We move all terms containing x to the left, all other terms to the right

3x=-8

x=-8/3

x=-2+2/3

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