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x(x+1)=(x+2)(x-4)
We move all terms to the left:
x(x+1)-((x+2)(x-4))=0
We multiply parentheses
x^2+x-((x+2)(x-4))=0
We multiply parentheses ..
x^2-((+x^2-4x+2x-8))+x=0
We calculate terms in parentheses: -((+x^2-4x+2x-8)), so:We add all the numbers together, and all the variables
(+x^2-4x+2x-8)
We get rid of parentheses
x^2-4x+2x-8
We add all the numbers together, and all the variables
x^2-2x-8
Back to the equation:
-(x^2-2x-8)
x^2+x-(x^2-2x-8)=0
We get rid of parentheses
x^2-x^2+x+2x+8=0
We add all the numbers together, and all the variables
3x+8=0
We move all terms containing x to the left, all other terms to the right
3x=-8
x=-8/3
x=-2+2/3
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