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x(x+1)=1200
We move all terms to the left:
x(x+1)-(1200)=0
We multiply parentheses
x^2+x-1200=0
a = 1; b = 1; c = -1200;
Δ = b2-4ac
Δ = 12-4·1·(-1200)
Δ = 4801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4801}}{2*1}=\frac{-1-\sqrt{4801}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4801}}{2*1}=\frac{-1+\sqrt{4801}}{2} $
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