x(x+1)=x(x-5)+6x

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Solution for x(x+1)=x(x-5)+6x equation:


Simplifying
x(x + 1) = x(x + -5) + 6x

Reorder the terms:
x(1 + x) = x(x + -5) + 6x
(1 * x + x * x) = x(x + -5) + 6x
(1x + x2) = x(x + -5) + 6x

Reorder the terms:
1x + x2 = x(-5 + x) + 6x
1x + x2 = (-5 * x + x * x) + 6x
1x + x2 = (-5x + x2) + 6x

Reorder the terms:
1x + x2 = -5x + 6x + x2

Combine like terms: -5x + 6x = 1x
1x + x2 = 1x + x2

Add '-1x' to each side of the equation.
1x + -1x + x2 = 1x + -1x + x2

Combine like terms: 1x + -1x = 0
0 + x2 = 1x + -1x + x2
x2 = 1x + -1x + x2

Combine like terms: 1x + -1x = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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