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x(x+10)=231
We move all terms to the left:
x(x+10)-(231)=0
We multiply parentheses
x^2+10x-231=0
a = 1; b = 10; c = -231;
Δ = b2-4ac
Δ = 102-4·1·(-231)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-32}{2*1}=\frac{-42}{2} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+32}{2*1}=\frac{22}{2} =11 $
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