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x(x+11)=1452
We move all terms to the left:
x(x+11)-(1452)=0
We multiply parentheses
x^2+11x-1452=0
a = 1; b = 11; c = -1452;
Δ = b2-4ac
Δ = 112-4·1·(-1452)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-77}{2*1}=\frac{-88}{2} =-44 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+77}{2*1}=\frac{66}{2} =33 $
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