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x(x+11)=63
We move all terms to the left:
x(x+11)-(63)=0
We multiply parentheses
x^2+11x-63=0
a = 1; b = 11; c = -63;
Δ = b2-4ac
Δ = 112-4·1·(-63)
Δ = 373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{373}}{2*1}=\frac{-11-\sqrt{373}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{373}}{2*1}=\frac{-11+\sqrt{373}}{2} $
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