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x(x+14)=312
We move all terms to the left:
x(x+14)-(312)=0
We multiply parentheses
x^2+14x-312=0
a = 1; b = 14; c = -312;
Δ = b2-4ac
Δ = 142-4·1·(-312)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-38}{2*1}=\frac{-52}{2} =-26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+38}{2*1}=\frac{24}{2} =12 $
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