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x(x+157)=2500
We move all terms to the left:
x(x+157)-(2500)=0
We multiply parentheses
x^2+157x-2500=0
a = 1; b = 157; c = -2500;
Δ = b2-4ac
Δ = 1572-4·1·(-2500)
Δ = 34649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(157)-\sqrt{34649}}{2*1}=\frac{-157-\sqrt{34649}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(157)+\sqrt{34649}}{2*1}=\frac{-157+\sqrt{34649}}{2} $
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