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x(x+19)=37
We move all terms to the left:
x(x+19)-(37)=0
We multiply parentheses
x^2+19x-37=0
a = 1; b = 19; c = -37;
Δ = b2-4ac
Δ = 192-4·1·(-37)
Δ = 509
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{509}}{2*1}=\frac{-19-\sqrt{509}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{509}}{2*1}=\frac{-19+\sqrt{509}}{2} $
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