x(x+2)(x-4)=-8

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Solution for x(x+2)(x-4)=-8 equation: 



x(x+2)(x-4)=-8

We move all terms to the left:

x(x+2)(x-4)-(-8)=0

We add all the numbers together, and all the variables

x(x+2)(x-4)+8=0

We multiply parentheses ..

x(+x^2-4x+2x-8)+8=0

We multiply parentheses

x^3-4x^2+2x^2-8x+8=0

We do not support expression: x^3

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