x(x+2)-10=x(7+2x)

Solution for x(x+2)-10=x(7+2x) equation:

x(x+2)-10=x(7+2x)

We move all terms to the left:

x(x+2)-10-(x(7+2x))=0

We add all the numbers together, and all the variables

x(x+2)-(x(2x+7))-10=0

We multiply parentheses

x^2+2x-(x(2x+7))-10=0


We calculate terms in parentheses: -(x(2x+7)), so:

x(2x+7)

We multiply parentheses

2x^2+7x

Back to the equation:

-(2x^2+7x)


We get rid of parentheses

x^2-2x^2+2x-7x-10=0

We add all the numbers together, and all the variables

-1x^2-5x-10=0

a = -1; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·(-1)·(-10)
Δ = -15
Delta is less than zero, so there is no solution for the equation