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x(x+2)=(x-2)(x+6)
We move all terms to the left:
x(x+2)-((x-2)(x+6))=0
We multiply parentheses
x^2+2x-((x-2)(x+6))=0
We multiply parentheses ..
x^2-((+x^2+6x-2x-12))+2x=0
We calculate terms in parentheses: -((+x^2+6x-2x-12)), so:We add all the numbers together, and all the variables
(+x^2+6x-2x-12)
We get rid of parentheses
x^2+6x-2x-12
We add all the numbers together, and all the variables
x^2+4x-12
Back to the equation:
-(x^2+4x-12)
x^2+2x-(x^2+4x-12)=0
We get rid of parentheses
x^2-x^2+2x-4x+12=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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