x(x+2)=-(x-1)(x-3)

Solution for x(x+2)=-(x-1)(x-3) equation:

x(x+2)=-(x-1)(x-3)

We move all terms to the left:

x(x+2)-(-(x-1)(x-3))=0

We multiply parentheses

x^2+2x-(-(x-1)(x-3))=0

We multiply parentheses ..

x^2-(-(+x^2-3x-1x+3))+2x=0


We calculate terms in parentheses: -(-(+x^2-3x-1x+3)), so:

-(+x^2-3x-1x+3)

We get rid of parentheses

-x^2+3x+1x-3

We add all the numbers together, and all the variables

-1x^2+4x-3

Back to the equation:

-(-1x^2+4x-3)


We get rid of parentheses

x^2+1x^2-4x+2x+3=0

We add all the numbers together, and all the variables

2x^2-2x+3=0

a = 2; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·2·3
Δ = -20
Delta is less than zero, so there is no solution for the equation