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x(x+2)=84
We move all terms to the left:
x(x+2)-(84)=0
We multiply parentheses
x^2+2x-84=0
a = 1; b = 2; c = -84;
Δ = b2-4ac
Δ = 22-4·1·(-84)
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{85}}{2*1}=\frac{-2-2\sqrt{85}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{85}}{2*1}=\frac{-2+2\sqrt{85}}{2} $
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