x(x+20)=210

Solution for x(x+20)=210 equation:

x(x+20)=210

We move all terms to the left:

x(x+20)-(210)=0

We multiply parentheses

x^2+20x-210=0

a = 1; b = 20; c = -210;
Δ = b2-4ac
Δ = 202-4·1·(-210)
Δ = 1240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1240}=\sqrt{4*310}=\sqrt{4}*\sqrt{310}=2\sqrt{310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{310}}{2*1}=\frac{-20-2\sqrt{310}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{310}}{2*1}=\frac{-20+2\sqrt{310}}{2}
$