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x(x+20)=2400
We move all terms to the left:
x(x+20)-(2400)=0
We multiply parentheses
x^2+20x-2400=0
a = 1; b = 20; c = -2400;
Δ = b2-4ac
Δ = 202-4·1·(-2400)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-100}{2*1}=\frac{-120}{2} =-60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+100}{2*1}=\frac{80}{2} =40 $
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