x(x+25)=1350

Solution for x(x+25)=1350 equation:

x(x+25)=1350

We move all terms to the left:

x(x+25)-(1350)=0

We multiply parentheses

x^2+25x-1350=0

a = 1; b = 25; c = -1350;
Δ = b2-4ac
Δ = 252-4·1·(-1350)
Δ = 6025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6025}=\sqrt{25*241}=\sqrt{25}*\sqrt{241}=5\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{241}}{2*1}=\frac{-25-5\sqrt{241}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{241}}{2*1}=\frac{-25+5\sqrt{241}}{2}
$