x(x+3)+2(x+3)+x(x-2)-3(x-2)-2x(x+1)=0

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Solution for x(x+3)+2(x+3)+x(x-2)-3(x-2)-2x(x+1)=0 equation: 



x(x+3)+2(x+3)+x(x-2)-3(x-2)-2x(x+1)=0

We multiply parentheses

x^2+x^2-2x^2+3x+2x-2x-3x-2x+6+6=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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