x(x+3)+5x=3+x(x-4)

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Solution for x(x+3)+5x=3+x(x-4) equation: 



x(x+3)+5x=3+x(x-4)

We move all terms to the left:

x(x+3)+5x-(3+x(x-4))=0

We add all the numbers together, and all the variables

5x+x(x+3)-(3+x(x-4))=0

We multiply parentheses

x^2+5x+3x-(3+x(x-4))=0



We calculate terms in parentheses: -(3+x(x-4)), so:

3+x(x-4)

determiningTheFunctionDomain
x(x-4)+3

We multiply parentheses

x^2-4x+3

Back to the equation:

-(x^2-4x+3)



We add all the numbers together, and all the variables

x^2+8x-(x^2-4x+3)=0

We get rid of parentheses

x^2-x^2+8x+4x-3=0

We add all the numbers together, and all the variables

12x-3=0

We move all terms containing x to the left, all other terms to the right

12x=3

x=3/12

x=1/4

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