x(x+3)-2=x(x+1)+6

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Solution for x(x+3)-2=x(x+1)+6 equation: 



x(x+3)-2=x(x+1)+6

We move all terms to the left:

x(x+3)-2-(x(x+1)+6)=0

We multiply parentheses

x^2+3x-(x(x+1)+6)-2=0



We calculate terms in parentheses: -(x(x+1)+6), so:

x(x+1)+6

We multiply parentheses

x^2+x+6

Back to the equation:

-(x^2+x+6)



We get rid of parentheses

x^2-x^2+3x-x-6-2=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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