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x(x+3)-x(x-4)=5(x-4)-7(x-3)
We move all terms to the left:
x(x+3)-x(x-4)-(5(x-4)-7(x-3))=0
We multiply parentheses
x^2-x^2+3x+4x-(5(x-4)-7(x-3))=0
We calculate terms in parentheses: -(5(x-4)-7(x-3)), so:We add all the numbers together, and all the variables
5(x-4)-7(x-3)
We multiply parentheses
5x-7x-20+21
We add all the numbers together, and all the variables
-2x+1
Back to the equation:
-(-2x+1)
7x-(-2x+1)=0
We get rid of parentheses
7x+2x-1=0
We add all the numbers together, and all the variables
9x-1=0
We move all terms containing x to the left, all other terms to the right
9x=1
x=1/9
x=1/9
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