If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(x+3)=504
We move all terms to the left:
x(x+3)-(504)=0
We multiply parentheses
x^2+3x-504=0
a = 1; b = 3; c = -504;
Δ = b2-4ac
Δ = 32-4·1·(-504)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-45}{2*1}=\frac{-48}{2} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+45}{2*1}=\frac{42}{2} =21 $
| | | y=15+6 | | 216-18x+x^2=224 | | |2x+15|=13 | | 4(8-3x)+6x=-6x+9 | | 224=216-18x+x^2 | | 224=216-18x=x^2 | | 16.6-5u=4.1 | | d^2+99d-100=0 | | 10.1=-9.1+6v | | -9.1=y/3+10.1 | | -9.1=y/3=10.1 | | 4+v/7=-4.75 | | p^2-99p-100=0 | | 5(3x+4)=25(x) | | 6(x-5)+3x=6x-10(-3+X) | | 5^(3x+4)=25^(x) | | (y-1/3)-(y+1/4)=y | | y-1/3-y+1/4=y | | 8x–3x+9=4x–1 | | 10×2+1=15+x÷3 | | t^2-3(2t+9)=0 | | 25x-3x+2=x-5 | | 4x-4=4x-4= | | 6(y-4)-4(5y+7)=3(y-2)-4(2y+1) | | -2(3x+10)=-9x+22+3x | | 18x−92x+1=2 | | 6×(x+1)÷4×x=16 | | 3x-(5-3x)=61 | | 18⋅x−92⋅x+1=2 | | -7x+4=3(x-3)+1 | | 7x-2x+12=8+4+5x |