x(x+3)=x2+4(x-3)

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Solution for x(x+3)=x2+4(x-3) equation: 



x(x+3)=x2+4(x-3)

We move all terms to the left:

x(x+3)-(x2+4(x-3))=0

We multiply parentheses

x^2+3x-(x2+4(x-3))=0



We calculate terms in parentheses: -(x2+4(x-3)), so:

x2+4(x-3)

We add all the numbers together, and all the variables

x^2+4(x-3)

We multiply parentheses

x^2+4x-12

Back to the equation:

-(x^2+4x-12)



We get rid of parentheses

x^2-x^2+3x-4x+12=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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