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x(x+36)=120
We move all terms to the left:
x(x+36)-(120)=0
We multiply parentheses
x^2+36x-120=0
a = 1; b = 36; c = -120;
Δ = b2-4ac
Δ = 362-4·1·(-120)
Δ = 1776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1776}=\sqrt{16*111}=\sqrt{16}*\sqrt{111}=4\sqrt{111}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{111}}{2*1}=\frac{-36-4\sqrt{111}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{111}}{2*1}=\frac{-36+4\sqrt{111}}{2} $
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