x(x+4)+20=2(x+2)

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Solution for x(x+4)+20=2(x+2) equation: 



x(x+4)+20=2(x+2)

We move all terms to the left:

x(x+4)+20-(2(x+2))=0

We multiply parentheses

x^2+4x-(2(x+2))+20=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

x^2+4x-2x-4+20=0

We add all the numbers together, and all the variables

x^2+2x+16=0

a = 1; b = 2; c = +16;
Δ = b2-4ac
Δ = 22-4·1·16
Δ = -60
Delta is less than zero, so there is no solution for the equation

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