x(x+4)+4-6x=6(1-x)+(x+4)(x+1)

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Solution for x(x+4)+4-6x=6(1-x)+(x+4)(x+1) equation: 



x(x+4)+4-6x=6(1-x)+(x+4)(x+1)

We move all terms to the left:

x(x+4)+4-6x-(6(1-x)+(x+4)(x+1))=0

We add all the numbers together, and all the variables

x(x+4)-6x-(6(-1x+1)+(x+4)(x+1))+4=0

We add all the numbers together, and all the variables

-6x+x(x+4)-(6(-1x+1)+(x+4)(x+1))+4=0

We multiply parentheses

x^2-6x+4x-(6(-1x+1)+(x+4)(x+1))+4=0

We multiply parentheses ..

x^2-(6(-1x+1)+(+x^2+x+4x+4))-6x+4x+4=0



We calculate terms in parentheses: -(6(-1x+1)+(+x^2+x+4x+4)), so:

6(-1x+1)+(+x^2+x+4x+4)

determiningTheFunctionDomain
(+x^2+x+4x+4)+6(-1x+1)

We multiply parentheses

(+x^2+x+4x+4)-6x+6

We get rid of parentheses

x^2+x+4x-6x+4+6

We add all the numbers together, and all the variables

x^2-1x+10

Back to the equation:

-(x^2-1x+10)



We add all the numbers together, and all the variables

x^2-2x-(x^2-1x+10)+4=0

We get rid of parentheses

x^2-x^2-2x+1x-10+4=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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