x(x+4)+5x=x(x-1)+20

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Solution for x(x+4)+5x=x(x-1)+20 equation: 



x(x+4)+5x=x(x-1)+20

We move all terms to the left:

x(x+4)+5x-(x(x-1)+20)=0

We add all the numbers together, and all the variables

5x+x(x+4)-(x(x-1)+20)=0

We multiply parentheses

x^2+5x+4x-(x(x-1)+20)=0



We calculate terms in parentheses: -(x(x-1)+20), so:

x(x-1)+20

We multiply parentheses

x^2-1x+20

Back to the equation:

-(x^2-1x+20)



We add all the numbers together, and all the variables

x^2+9x-(x^2-1x+20)=0

We get rid of parentheses

x^2-x^2+9x+1x-20=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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