x(x+40)+30=180

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Solution for x(x+40)+30=180 equation:



x(x+40)+30=180
We move all terms to the left:
x(x+40)+30-(180)=0
We add all the numbers together, and all the variables
x(x+40)-150=0
We multiply parentheses
x^2+40x-150=0
a = 1; b = 40; c = -150;
Δ = b2-4ac
Δ = 402-4·1·(-150)
Δ = 2200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2200}=\sqrt{100*22}=\sqrt{100}*\sqrt{22}=10\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-10\sqrt{22}}{2*1}=\frac{-40-10\sqrt{22}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+10\sqrt{22}}{2*1}=\frac{-40+10\sqrt{22}}{2} $

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