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x(x+5)-5(x-7)=0
We multiply parentheses
x^2+5x-5x+35=0
We add all the numbers together, and all the variables
x^2+35=0
a = 1; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·1·35
Δ = -140
Delta is less than zero, so there is no solution for the equation
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