x(x+5)=(x-4)(x-3)

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Solution for x(x+5)=(x-4)(x-3) equation: 



x(x+5)=(x-4)(x-3)

We move all terms to the left:

x(x+5)-((x-4)(x-3))=0

We multiply parentheses

x^2+5x-((x-4)(x-3))=0

We multiply parentheses ..

x^2-((+x^2-3x-4x+12))+5x=0



We calculate terms in parentheses: -((+x^2-3x-4x+12)), so:

(+x^2-3x-4x+12)

We get rid of parentheses

x^2-3x-4x+12

We add all the numbers together, and all the variables

x^2-7x+12

Back to the equation:

-(x^2-7x+12)



We add all the numbers together, and all the variables

x^2+5x-(x^2-7x+12)=0

We get rid of parentheses

x^2-x^2+5x+7x-12=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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