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x(x+7)=228
We move all terms to the left:
x(x+7)-(228)=0
We multiply parentheses
x^2+7x-228=0
a = 1; b = 7; c = -228;
Δ = b2-4ac
Δ = 72-4·1·(-228)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-31}{2*1}=\frac{-38}{2} =-19 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+31}{2*1}=\frac{24}{2} =12 $
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