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x(x+8)-(5x^2=+3x)
We move all terms to the left:
x(x+8)-(5x^2-(+3x))=0
We multiply parentheses
x^2+8x-(5x^2-(+3x))=0
We calculate terms in parentheses: -(5x^2-(+3x)), so:We get rid of parentheses
5x^2-(+3x)
We get rid of parentheses
5x^2-3x
Back to the equation:
-(5x^2-3x)
x^2-5x^2+8x+3x=0
We add all the numbers together, and all the variables
-4x^2+11x=0
a = -4; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-4)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-4}=\frac{-22}{-8} =2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-4}=\frac{0}{-8} =0 $
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