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x(x+8)=192
We move all terms to the left:
x(x+8)-(192)=0
We multiply parentheses
x^2+8x-192=0
a = 1; b = 8; c = -192;
Δ = b2-4ac
Δ = 82-4·1·(-192)
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{13}}{2*1}=\frac{-8-8\sqrt{13}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{13}}{2*1}=\frac{-8+8\sqrt{13}}{2} $
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