x(x-1)(x+1)(x-2)(x+3)=144

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Solution for x(x-1)(x+1)(x-2)(x+3)=144 equation: 



x(x-1)(x+1)(x-2)(x+3)=144

We move all terms to the left:

x(x-1)(x+1)(x-2)(x+3)-(144)=0

We multiply parentheses ..

x(+x^2+x-1x-1)(x-2)(x+3)-144=0

We multiply parentheses ..

x(+x^2+x-1x-1)(+x^2+3x-2x-6)-144=0

We move all terms containing x to the left, all other terms to the right

x(+x^2+x-1x-1)(+x^2+3x-2x-6)=144

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