x(x-1)-6=(x-3)(x+2)

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Solution for x(x-1)-6=(x-3)(x+2) equation:



x(x-1)-6=(x-3)(x+2)
We move all terms to the left:
x(x-1)-6-((x-3)(x+2))=0
We multiply parentheses
x^2-1x-((x-3)(x+2))-6=0
We multiply parentheses ..
x^2-((+x^2+2x-3x-6))-1x-6=0
We calculate terms in parentheses: -((+x^2+2x-3x-6)), so:
(+x^2+2x-3x-6)
We get rid of parentheses
x^2+2x-3x-6
We add all the numbers together, and all the variables
x^2-1x-6
Back to the equation:
-(x^2-1x-6)
We add all the numbers together, and all the variables
x^2-1x-(x^2-1x-6)-6=0
We get rid of parentheses
x^2-x^2-1x+1x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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