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x(x-10)=22
We move all terms to the left:
x(x-10)-(22)=0
We multiply parentheses
x^2-10x-22=0
a = 1; b = -10; c = -22;
Δ = b2-4ac
Δ = -102-4·1·(-22)
Δ = 188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{188}=\sqrt{4*47}=\sqrt{4}*\sqrt{47}=2\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{47}}{2*1}=\frac{10-2\sqrt{47}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{47}}{2*1}=\frac{10+2\sqrt{47}}{2} $
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