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x(x-12)=30+x(x-6)+8
We move all terms to the left:
x(x-12)-(30+x(x-6)+8)=0
We multiply parentheses
x^2-12x-(30+x(x-6)+8)=0
We calculate terms in parentheses: -(30+x(x-6)+8), so:We get rid of parentheses
30+x(x-6)+8
determiningTheFunctionDomain x(x-6)+30+8
We add all the numbers together, and all the variables
x(x-6)+38
We multiply parentheses
x^2-6x+38
Back to the equation:
-(x^2-6x+38)
x^2-x^2-12x+6x-38=0
We add all the numbers together, and all the variables
-6x-38=0
We move all terms containing x to the left, all other terms to the right
-6x=38
x=38/-6
x=-6+1/3
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