x(x-12)=30+x(x-6)+8

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Solution for x(x-12)=30+x(x-6)+8 equation: 



x(x-12)=30+x(x-6)+8

We move all terms to the left:

x(x-12)-(30+x(x-6)+8)=0

We multiply parentheses

x^2-12x-(30+x(x-6)+8)=0



We calculate terms in parentheses: -(30+x(x-6)+8), so:

30+x(x-6)+8

determiningTheFunctionDomain
x(x-6)+30+8

We add all the numbers together, and all the variables

x(x-6)+38

We multiply parentheses

x^2-6x+38

Back to the equation:

-(x^2-6x+38)



We get rid of parentheses

x^2-x^2-12x+6x-38=0

We add all the numbers together, and all the variables

-6x-38=0

We move all terms containing x to the left, all other terms to the right

-6x=38

x=38/-6

x=-6+1/3

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