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x(x-17)-18x=(x-3)(x+10)
We move all terms to the left:
x(x-17)-18x-((x-3)(x+10))=0
We add all the numbers together, and all the variables
-18x+x(x-17)-((x-3)(x+10))=0
We multiply parentheses
x^2-18x-17x-((x-3)(x+10))=0
We multiply parentheses ..
x^2-((+x^2+10x-3x-30))-18x-17x=0
We calculate terms in parentheses: -((+x^2+10x-3x-30)), so:We add all the numbers together, and all the variables
(+x^2+10x-3x-30)
We get rid of parentheses
x^2+10x-3x-30
We add all the numbers together, and all the variables
x^2+7x-30
Back to the equation:
-(x^2+7x-30)
x^2-35x-(x^2+7x-30)=0
We get rid of parentheses
x^2-x^2-35x-7x+30=0
We add all the numbers together, and all the variables
-42x+30=0
We move all terms containing x to the left, all other terms to the right
-42x=-30
x=-30/-42
x=5/7
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