x(x-17)-18x=(x-3)(x+15)

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Solution for x(x-17)-18x=(x-3)(x+15) equation: 



x(x-17)-18x=(x-3)(x+15)

We move all terms to the left:

x(x-17)-18x-((x-3)(x+15))=0

We add all the numbers together, and all the variables

-18x+x(x-17)-((x-3)(x+15))=0

We multiply parentheses

x^2-18x-17x-((x-3)(x+15))=0

We multiply parentheses ..

x^2-((+x^2+15x-3x-45))-18x-17x=0



We calculate terms in parentheses: -((+x^2+15x-3x-45)), so:

(+x^2+15x-3x-45)

We get rid of parentheses

x^2+15x-3x-45

We add all the numbers together, and all the variables

x^2+12x-45

Back to the equation:

-(x^2+12x-45)



We add all the numbers together, and all the variables

x^2-35x-(x^2+12x-45)=0

We get rid of parentheses

x^2-x^2-35x-12x+45=0

We add all the numbers together, and all the variables

-47x+45=0

We move all terms containing x to the left, all other terms to the right

-47x=-45

x=-45/-47

x=45/47

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