x(x-2)(x2+x+6)(x+2)(x2-2x+4)=0

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Solution for x(x-2)(x2+x+6)(x+2)(x2-2x+4)=0 equation: 



x(x-2)(x2+x+6)(x+2)(x2-2x+4)=0

We add all the numbers together, and all the variables

x(x-2)(+x^2+x+6)(x+2)(+x^2-2x+4)=0

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