x(x-2)+12=x(x+4)

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Solution for x(x-2)+12=x(x+4) equation: 



x(x-2)+12=x(x+4)

We move all terms to the left:

x(x-2)+12-(x(x+4))=0

We multiply parentheses

x^2-2x-(x(x+4))+12=0



We calculate terms in parentheses: -(x(x+4)), so:

x(x+4)

We multiply parentheses

x^2+4x

Back to the equation:

-(x^2+4x)



We get rid of parentheses

x^2-x^2-2x-4x+12=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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