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x(x-23)=17(x-23)
We move all terms to the left:
x(x-23)-(17(x-23))=0
We multiply parentheses
x^2-23x-(17(x-23))=0
We calculate terms in parentheses: -(17(x-23)), so:We get rid of parentheses
17(x-23)
We multiply parentheses
17x-391
Back to the equation:
-(17x-391)
x^2-23x-17x+391=0
We add all the numbers together, and all the variables
x^2-40x+391=0
a = 1; b = -40; c = +391;
Δ = b2-4ac
Δ = -402-4·1·391
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-6}{2*1}=\frac{34}{2} =17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+6}{2*1}=\frac{46}{2} =23 $
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