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x(x-24)=945
We move all terms to the left:
x(x-24)-(945)=0
We multiply parentheses
x^2-24x-945=0
a = 1; b = -24; c = -945;
Δ = b2-4ac
Δ = -242-4·1·(-945)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-66}{2*1}=\frac{-42}{2} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+66}{2*1}=\frac{90}{2} =45 $
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