x(x-3)+x(x+5)=2x(x+1)

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Solution for x(x-3)+x(x+5)=2x(x+1) equation: 



x(x-3)+x(x+5)=2x(x+1)

We move all terms to the left:

x(x-3)+x(x+5)-(2x(x+1))=0

We multiply parentheses

x^2+x^2-3x+5x-(2x(x+1))=0



We calculate terms in parentheses: -(2x(x+1)), so:

2x(x+1)

We multiply parentheses

2x^2+2x

Back to the equation:

-(2x^2+2x)



We add all the numbers together, and all the variables

2x^2+2x-(2x^2+2x)=0

We get rid of parentheses

2x^2-2x^2+2x-2x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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