x(x-3)=(x-3)(x+5)

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Solution for x(x-3)=(x-3)(x+5) equation: 



x(x-3)=(x-3)(x+5)

We move all terms to the left:

x(x-3)-((x-3)(x+5))=0

We multiply parentheses

x^2-3x-((x-3)(x+5))=0

We multiply parentheses ..

x^2-((+x^2+5x-3x-15))-3x=0



We calculate terms in parentheses: -((+x^2+5x-3x-15)), so:

(+x^2+5x-3x-15)

We get rid of parentheses

x^2+5x-3x-15

We add all the numbers together, and all the variables

x^2+2x-15

Back to the equation:

-(x^2+2x-15)



We add all the numbers together, and all the variables

x^2-3x-(x^2+2x-15)=0

We get rid of parentheses

x^2-x^2-3x-2x+15=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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