x(x-4)+(x-4)=(x-4)(x+1)

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Solution for x(x-4)+(x-4)=(x-4)(x+1) equation: 



x(x-4)+(x-4)=(x-4)(x+1)

We move all terms to the left:

x(x-4)+(x-4)-((x-4)(x+1))=0

We multiply parentheses

x^2-4x+(x-4)-((x-4)(x+1))=0

We get rid of parentheses

x^2-4x+x-((x-4)(x+1))-4=0

We multiply parentheses ..

x^2-((+x^2+x-4x-4))-4x+x-4=0



We calculate terms in parentheses: -((+x^2+x-4x-4)), so:

(+x^2+x-4x-4)

We get rid of parentheses

x^2+x-4x-4

We add all the numbers together, and all the variables

x^2-3x-4

Back to the equation:

-(x^2-3x-4)



We add all the numbers together, and all the variables

x^2-3x-(x^2-3x-4)-4=0

We get rid of parentheses

x^2-x^2-3x+3x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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