x(x-4)+(x-4)=(x-4)(x+1)

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Solution for x(x-4)+(x-4)=(x-4)(x+1) equation:



x(x-4)+(x-4)=(x-4)(x+1)
We move all terms to the left:
x(x-4)+(x-4)-((x-4)(x+1))=0
We multiply parentheses
x^2-4x+(x-4)-((x-4)(x+1))=0
We get rid of parentheses
x^2-4x+x-((x-4)(x+1))-4=0
We multiply parentheses ..
x^2-((+x^2+x-4x-4))-4x+x-4=0
We calculate terms in parentheses: -((+x^2+x-4x-4)), so:
(+x^2+x-4x-4)
We get rid of parentheses
x^2+x-4x-4
We add all the numbers together, and all the variables
x^2-3x-4
Back to the equation:
-(x^2-3x-4)
We add all the numbers together, and all the variables
x^2-3x-(x^2-3x-4)-4=0
We get rid of parentheses
x^2-x^2-3x+3x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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