x(x-4)+4x-2=x(x+4)

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Solution for x(x-4)+4x-2=x(x+4) equation: 



x(x-4)+4x-2=x(x+4)

We move all terms to the left:

x(x-4)+4x-2-(x(x+4))=0

We add all the numbers together, and all the variables

4x+x(x-4)-(x(x+4))-2=0

We multiply parentheses

x^2+4x-4x-(x(x+4))-2=0



We calculate terms in parentheses: -(x(x+4)), so:

x(x+4)

We multiply parentheses

x^2+4x

Back to the equation:

-(x^2+4x)



We add all the numbers together, and all the variables

x^2-(x^2+4x)-2=0

We get rid of parentheses

x^2-x^2-4x-2=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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