x(x-4)=(x+6)(x-2)

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Solution for x(x-4)=(x+6)(x-2) equation: 



x(x-4)=(x+6)(x-2)

We move all terms to the left:

x(x-4)-((x+6)(x-2))=0

We multiply parentheses

x^2-4x-((x+6)(x-2))=0

We multiply parentheses ..

x^2-((+x^2-2x+6x-12))-4x=0



We calculate terms in parentheses: -((+x^2-2x+6x-12)), so:

(+x^2-2x+6x-12)

We get rid of parentheses

x^2-2x+6x-12

We add all the numbers together, and all the variables

x^2+4x-12

Back to the equation:

-(x^2+4x-12)



We add all the numbers together, and all the variables

x^2-4x-(x^2+4x-12)=0

We get rid of parentheses

x^2-x^2-4x-4x+12=0

We add all the numbers together, and all the variables

-8x+12=0

We move all terms containing x to the left, all other terms to the right

-8x=-12

x=-12/-8

x=1+1/2

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